Q.

Number of four-digit numbers of the form N=abcd  which satisfy following three conditions

i) 4000N<6000  
ii) N is a multiple of 5
iii)  3b<c6
is_______

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answer is 24.

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Detailed Solution

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We have  Question Image

First place a can be filled in 2 ways, i.e.   4,5(4000N<6000)
For b and c, total possibilities are  6(3b<c6)
i.e.,  34,35,36,45,46,56
Last place d can be filled in 2 ways, i.e.,0,5(N is a multiple of 5)
Hence, total numbers  =2×6×2=24

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