Number of grams of bromine that will completely react with $5.0 g$ of pent- 1 -ene is ____________x $10^{- 2} g$ . (Atomic mass of $Br = 80 g / mol$ ) [Nearest Integer)

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answer is 1143.

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Detailed Solution

$moles of {Br}_{2} = moles of C_{5} H_{10} \begin{aligned} \Rightarrow \frac{W}{160} = \frac{5}{70} \\ \Rightarrow W = \frac{5 \times 160}{70} g \\ = 11.428 g \\ = 1142.8 \times 10^{- 2} g \approx 1143 \times 10^{- 2} g \end{aligned}$

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