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Number of $H^{+}$ ions present in 10mL of solution of $P^{H} = 3$ are :

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$10^{13}$

$6.02 \times 10^{18}$

$6.02 \times 10^{13}$

$6.02 \times 10^{10}$

answer is B.

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Detailed Solution

$[H^{+}] = 10^{- 3} = \frac{n}{10} \times 1000$
$\begin{aligned} ∴ n = 10^{- 5} \\ 1 mole = 6 \times 10^{23} ions \\ 10^{- 5} mole = 6 \times 10^{18} ions \end{aligned}$

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