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Q.

Number of hydrogen ions present in 10 millionth part of 1.33 cm3 of pure water at 25° C is

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a

6.023 million

b

60 million

c

8.01 million

d

80.23 million

answer is C.

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Detailed Solution

10 million =10−7

∴ 10 millionth part of 1.33 cm3 = 1.33 × 10−7cm3 = 1.33 × 10−7 mL

For pure water, [H+]=10−7 mol/L

⇒ 1L water contains [H+]=10−7 moles

or 1mL water contains [H+] = 10-71000​=10−10 moles

or 10 millionth part of 1.33 cm3 water contains

[H+] = 1.33 × 10−7 × 10−10 moles = 1.33 × 10−17 moles

∴ Number of H+ ions =1.33×10−17 × NA

= 1.33 × 10−7 × 6.022 ×1023

= 8.009 × 106 = 8.01 million

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