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Q.

Number of ions present in K4[Fe(CN)6] is

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a

2

b

10

c

3

d

5

answer is D.

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Detailed Solution

  • K4FeCN6 is a complex salt. 
  • On ionization it will dissociate in 4K+ and  FeCN64−ion. 
  • Hence, in K4FeCN6, five ions are present.
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