Number of isomers for the compound with the molecular formula  ${\mathrm{C}}_2\mathrm{BrClFI}$  is

Number of Isomers for C₂BrClFI

The molecule has two carbons and four different halogens (Br, Cl, F, I). Distributing four distinct substituents across two equivalent carbon centers (each bearing two substituents) leads to multiple distinct arrangements.

Total isomers = 6

Intuition: Arrange the four different halogens into two unordered pairs for the two carbons. The count is 4! / 2 = 12 / 2 = 6, since swapping the two carbons does not create a new structure.