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Q.

Number of lone pairs of electrons present is NH3,H2O, HF respectively are 

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a

2,1,3

b

3,2,1

c

1,2,3

d

3,1,2

answer is C.

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Detailed Solution

NH3​: 3 bond pairs and one lone pair because, out of 5 valence electrons of nitrogen, only 2 electrons are left to form a lone pair.

H2​O: 2 bond pairs and two lone pairs because, out of 6 valence electrons of oxygen, 4 electrons are left to form 2 lone pairs.

HF: 3 lone pairs and 1 bond pair.
 

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