Number of lone pairs of electrons present is $N H_{3}, H_{2} O, H F$ respectively are

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3,1,2

2,1,3

1,2,3

3,2,1

answer is C.

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Detailed Solution

NH₃: 3 bond pairs and one lone pair because, out of 5 valence electrons of nitrogen, only 2 electrons are left to form a lone pair.

H₂O: 2 bond pairs and two lone pairs because, out of 6 valence electrons of oxygen, 4 electrons are left to form 2 lone pairs.

HF: 3 lone pairs and 1 bond pair.

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