Number of molecules in which all the equatorial $M-X$ bonds are smaller as compared to axial $M-X$ bonds (M = Central atom, X = halogen bonded with central atom) 

${\mathrm{PCl}}_3{\mathrm{F}}_2,{\mathrm{PCl}}_2{\mathrm{F}}_3,{\mathrm{PCl}}_5,{\mathrm{SeF}}_6,{\mathrm{IF}}_7,{\mathrm{SOF}}_4,{\mathrm{ClF}}_3$

In $PC{l}_5$ every atom in the vicinity of P is essentially the same, i.e. Cl. Therefore, the reason why axial bonds in instance $PC{l}_5$ are longer than equatorial bonds cannot be explained by the electronegativity factor of Cl. The axial bonds in $PC{l}_5$ are repelled by the equatorial bonds, which causes them to lengthen. 

Number of equatorial bonds in  $PC{l}_5$

There are 3 equatorial and 2 axial P-Cl bonds