Number of molecules of alkene required for the reaction of one molecule of B2H6 to carry out hydorboration

B2H6⇌2BH3BH3 is having 3 H -atoms requires 3 molecules of alkene2 BH3 requires 6 molecules of alkene

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Number of molecules of alkene required for the reaction of one molecule of B₂H₆ to carry out hydorboration

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answer is 6.

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B₂H₆ $⇌$ 2BH₃

BH₃ is having 3 H -atoms requires 3 molecules of alkene

2 BH₃ requires 6 molecules of alkene

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