Number of moles MnO₄^– required to oxidize one mole of ferrous oxalate completely in acidic medium will be

In acidic medium ${\mathrm{MnO}}_4^{-}$ oxidizes Ferrous oxalate as follows:

$2{\mathrm{MnO}}_4^{-}+5{\mathrm{C}}_2{\mathrm{O}}_4^{-2}+16{\mathrm{H}}^{+}\to 2{\mathrm{Mn}}^{2+}+10{\mathrm{CO}}_2+8{\mathrm{H}}_2\mathrm{O}$

5 moles of oxalate ions are oxidized by 2 moles of ${\mathrm{MnO}}_4^{-}$

1 mole of oxalate ion is oxidized by ---------------?

$\frac{2}{5}\mathrm{moles} \mathrm{of} {\mathrm{MnO}}_4^{-}$

= 0.4 moles