Number of moles of ${KMnO}_4$ required to oxidize one mole of $Fe\left(C_2{O}_4\right)$ in acidic medium is

The given reaction is as follows:

${MnO}_4^{-}+{Fe}^{2+}+C_2{O}_4^{2-}⟶{Mn}^{2+}+{Fe}^{3+}+{CO}_2$

The oxidation state of manganese changes from 7 to 2 therefore the n-factor is 5

n-factor of ${\mathrm{C}}_2{\mathrm{O}}_4^{2-}$ is 3

using the relation : moles $\times$ n=factor when number of equivalents are equal on both sides.

moles$\times$5=3$\times$1

Therefore moles = 0.6

Hence the correct option is (A).