Number of moles present in 22 grams of carbon dioxide

${\text{1\hspace{0.17em}mole\hspace{0.17em}of CO}}_2\to 44{\text{\hspace{0.17em}g\hspace{0.17em}of CO}}_{\text{2}}$

$x{\text{\hspace{0.17em}\hspace{0.17em}moles\hspace{0.17em}of CO}}_{\text{2}}?\to 22{\text{\hspace{0.17em}g of CO}}_{\text{2}}$

Then number of moles of ${\text{CO}}_{\text{2}}$ gas present in

$\therefore x=\frac{1.0\text{\hspace{0.17em}mol}}{44\text{\hspace{0.17em}g}}\times 22\text{\hspace{0.17em}g}=0.5\text{\hspace{0.17em}mol}$