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Q.

Number of negative integral values of x satisfying 4x+0.57.2x<4,xR is 

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a

2

b

1

c

0

d

3

answer is A.

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Detailed Solution

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4x+0.57.2x<4------(1)

 Let 2x=t t>0----(2)

  (1) reduces to 2t27t<4 2t27t4<0 (2t+1)(t4)<0

 12<t<4---(3)

⇒ from (2) and (3)                                                                                                                                                       0<t<4                                                                                                                                                                               0<2x<4         since 2-x<4 -x< log4 2 -x<2 x>-2                                                                                     2<x<                                                                                                                                                                                                 x(2,)   x=-1 is the only negative value                                                                                                                          

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