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Number of neutrons in $_{51}^{121} Sb$ is ____.

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Detailed Solution

Number of neutrons in

_{51}^{121} Sb

70

.
Here

_{51}^{121} Sb

has atomic number

51

and we know that the atomic number of an element is equal to the number of protons present in it.
Therefore number of protons in the given element is

51

As we know, the sum of protons and neutrons is called the mass number of an element.
Then mass number of given element is

121

.
Therefore number of neutron is

121 - 51 = 70

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