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Number of ordered triplets of natural numbers (a, b, c) for which abc $\leq$ 11

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answer is D.

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Detailed Solution

abc= 1 m 1 way

abc= 2,3,5,7,11 m 15 ways

abc= 4,9, m 12 ways

abc = 8 m 10ways

abc= 6,10 m 18 ways
Total = 56

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