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Q.

Number of points of discontinuity of f(x)=[2x35] in [1,2), is equal to: (where  [x] denotes greatest integer less than or equal to x)

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a

8

b

13

c

10

d

14

answer is A.

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Detailed Solution

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f(x)=[2x35]=[2x3]5

Let 2x3=t

   g(t)=[t] where t[2,16)

g is continuous at t=2 and discontinuous  t=3,4,.......,15=13 points. 

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