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Number of primary, secondary, tertiary and neo carbons in the following compound respectively are

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5, 1, 1, 1

3, 2, 2, 1

4, 2, 1, 1

5, 0, 2, 1

answer is B.

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Detailed Solution

4° a carbon which joins with 4 other carbons.

1° − 5

2° − 1

3° − 1

4° − 1

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