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Q.

Number of values of x0,2π satisfying sinx+sin2x+sin3x=cosx+cos2x+cos3x is_______

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answer is 6.

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Detailed Solution

sinx+sin2x+sin3x=cosx+cos2x+cos3x sin3x+sinx+sin2x=cos3x+cosx+cos2x 2sin2x cosx+sin2x=2cos2xcosx+cos2x sin2x(2cosx+1)-cos2x(2cos x+1)=0 2cosx+1(sin2x-cos2x)=0 cosx=-12     tan2x=1 x=2π3,4π3   2x=π4,5π4,9π4                            x=π8,3π8,9π8,13π8 No.of solutions 6

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