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Number of waves produced by an electron in one complete revolution in nth orbit is:

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$n$

$(2 n + 1)$

$n^{2}$

$(n + 1)$

answer is A.

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Detailed Solution

$E_{n} = \frac{1}{2} P . E . = - \frac{6.8}{2} = - 3.4 e V$
$∵ E_{n} \Rightarrow \frac{- 13.6}{n^{2}} = - 3.4$
n=2 or first excited state

$334 = (\frac{36}{5} - \frac{4}{3}) \times \frac{1}{R_{H}} \times \frac{1}{Z^{2}} 334 = (7.2 - 1.33) \times 912 \times \frac{1}{Z^{2}} Z^{2} = \frac{5.86 \times 912}{334} = 16 Z = 4$

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