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Q.

Number of ways in which 9 different toys be distributed among 4 children belonging to different age groups in such way that distribution among the three elder children is even and the youngest one is to receive one toy more is N then 2N7!= _______

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answer is 3.

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Detailed Solution

Distribution 2,2,2 and 3 to the youngest. Now 3 toys for the youngest can be selected in  9C3  way, remaining 6 toys can be divided into three equal groups in 6!(2!)33! ways and can be distributed in  3! ways →9C3.6!(21)3=93!.8

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