Number of zeros at the end of ${99}^{1001}+1$ is _________

${99}^{1001}+1={\left(100-1\right)}^{1001}+1$

$={100}^{1001}{-}^{1001}{C}_1{100}^{1000}+\mathrm{......}{+}^{1001}{C}_{1000}100-1+1$

$=100m{+}^{1001}{C}_{1000}\left(100\right)$

$=100m+100100$