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Q.

Number of B-O linkage in NaB3O3(OH)=x

Number of peroxy linkage in Na2B2O4(OH)4=y

Number of tetrahedral units of B in Na2B4O5(OH)4=z

Find the value of x(y+z)

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answer is 6.

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Detailed Solution

The structure of NaB3O3(OH) can be given as,

Question Image

Here, the number of B-O linkage,

x=10

The structure of Na2B2O4(OH)4 can be given as,

Question Image

Here, the number of peroxy  linkage,

y=2

The structure of Na2B4O5(OH)4 can be given as,

Question Image

Here, the number of tetrahedral  linkage,

z=2

Thus,

x-(y+z) =10-(2+2) =6

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