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Q.

Number of pπdπ bond(s) in SO2Cl2 is/are:

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a

2

b

1

c

0

d

3

answer is D.

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Detailed Solution

Sulphur has sp2 hybridization.

These hybrid orbitals contain a lone pair as well as two bond pairs (due to sigma bonding). The 3p and 3d hybridized orbitals of the unpaired electrons in oxygen are combined with the 2p unhybridized orbitals to form a pi bond. 

Thus, two pπdπ, are created

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