‘O’ is the center of a square ABCD. F1,F2,F3 and F4 are four forces acting along the sides AB, BC, CD and AD as shown in figure. What should be the magnitude of F4 so that, the total torque about ‘O’ is zero?

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‘O’ is the center of a square ABCD. $F_{1}, F_{2}, F_{3} and F_{4}$ are four forces acting along the sides AB, BC, CD and AD as shown in figure. What should be the magnitude of F₄ so that, the total torque about ‘O’ is zero?

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$\frac{F_{1} + F_{2} + F_{3}}{2}$

$F_{1} - F_{2} - F_{3}$

$F_{1} + F_{2} - F_{3}$

$F_{1} + F_{2} + F_{3}$

answer is C.

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Detailed Solution

The Torques for all three forces F₁, F₂, F₃ are in same direction,

So the magnitude of F₄ must be equal to sum of all three forces.

$F_{4} = F_{1} + F_{2} + F_{3}$

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