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Q.

‘O’ is the center of a square ABCD. F1,F2,F3 and F4 are four forces acting along the sides AB, BC, CD and AD as shown in figure. What should be the magnitude of F4 so that, the total torque about ‘O’ is zero?

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a

F1−F2−F3

b

F1+F2−F3

c

F1+F2+F3

d

F1+F2+F32

answer is C.

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Detailed Solution

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The Torques for all three forces F1, F2, F3 are in same direction, 

So the magnitude of F4 must be equal to sum of all three forces.

F4=F1+F2+F3

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