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Q.

O2+2H++2eH2O2......E0=+0.68V

 MnO4+8H++5eMn2++4H2O......E0=+1.51V

 I2+2e2I......E0=+0.54V

Identify the incorrect statement based on the above data is

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a

H2O2 can reduce I2 to I in acidic medium 

b

KMnO4 can oxidizeH2O2 to O2 in acidic medium 

c

KMnO4 can oxidize I to I2 in acidic medium

d

Oxidizing power of  MnO4>O2>I2

answer is B.

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Detailed Solution

   H2O2O2+2H++2e       E0=0.68VI2+2e2I                               E0=+0.54V_H2O2+I22I+2H+       Ecell0=(ve)

Hence H2O2 can not reduce I2 to I

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