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Q.

O₂ is bubbled through water at 293K, assuming that O₂ exerts a partial pressure of 0.98 bar, the solubility of O₂ in gm.L^–1 is (Henry's law constant = 34 k bar)

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a

0.025

b

0.05

c

0.1

d

0.2

answer is B.

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Detailed Solution

$p_{O_{2}} = K_{H} . \frac{n_{O_{2}}}{n_{H_{2} O}} (n_{O_{2}} in the denominator is neglected) 0.98 = 34 \times 10^{3} \times \frac{n_{O_{2}}}{\frac{1000}{18}}; n_{O_{2}} = \frac{0.98}{18 \times 34}; W_{O_{2}} = \frac{0.98 \times 32}{18 \times 34} = 0.05 g;$

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O2 is bubbled through water at 293K, assuming that O2 exerts a partial pressure of 0.98 bar, the solubility of O2 in gm.L–1 is (Henry's law constant = 34 k bar)