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$O_{2}$ molecule is paramagnetic because it contains

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two unpaired electrons in $\overset{*}{π}$ $2 p_{x}$ molecular orbital

two unpaired electrons in $\overset{*}{π}$ $2 p_{z}$ orbitals.

two unpaired electrons in $\overset{*}{π}$ $2 p_{x}$ and $\overset{*}{π}$ $2 p_{y}$ molecular orbitals

two unpaired electrons in $\overset{*}{π}$ $2 p_{y}$ molecular orbital

answer is C.

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Detailed Solution

$O_{2} = KK (σ 2 s)^{2} (σ 2 s)^{2} {(σ 2 p_{z})}^{2} {(π 2 p_{x}^{2} = π 2 p_{y})}^{2}$ $(π 2 p_{x}^{1} = π^{*} 2 p_{y}^{1})$

It is paramagnetic because of two unpaired electrons in $\overset{*}{π}$ $2 p_{x}$ and $\overset{*}{π}$ $2 p_{y}$ molecular orbitals.

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