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Q.

OA,OB,OC are three rays in order that AOB=72°,BOC=26°,OP bisects AOC,  then the value of POC is

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a

59°

b

48°

c

49°

d

39°

answer is A.

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Detailed Solution

AOC=AOB+BOC   =72°+26°=98°OP  bisects  AOCAOP=POC=12AOC=12×98°  =49°

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OA→,OB→,OC→ are three rays in order that  AOB=72°,BOC=26°,OP → bisects AOC,  then the value of POC is