Q.

Object O is placed at a distance of 14cm from an equi convex lens L1 of refractive index μ=32  and radius of curvature of lens surface is 32 cm. One of its surface is silvered another convex lens  L2  of focal length 24 cm is placed between object and silvered lens such that the final image coincides with the object. The distance between object and the lens L2  in cm is ……… ( Take first Refraction from Lens  L2 ) 
 

Question Image

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

answer is 6.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

detailed_solution_thumbnail

1v1x=124 1v=1241x 1v=1(24x24x)

Object distance for silvered lens is  (14x)+24x(24x) for image to be an object O, this distance must be equal to equivalent radius of mirror.
For (Reflecting lens is effectively mirror)

2Req=2(321)(132132)332 Req=16cm 16=(14x)+24x(24x) x=6cm

Watch 3-min video & get full concept clarity

tricks from toppers of Infinity Learn

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon