Observe the following lists List I List IIA)∫−2214+x2dx1)π3B)∫121xx2−1dx2)0C)∫0πcos3x.cos2x dx3)π4 4)π2The correct match for List I from List II

A=12tan−1(x2) B=(sec−1) 1 2 C=∫02af(x)dx=0 if f(2a−x)=−f(x)

Observe the following lists List I List IIA)∫−2214+x2dx1)π3B)∫121xx2−1dx2)0C)∫0πcos3x.cos2x dx3)π4 4)π2The correct match for List I from List II

A=12tan−1(x2) B=(sec−1) 1 2 C=∫02af(x)dx=0 if f(2a−x)=−f(x)

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Observe the following lists
List I List II
A) $\int_{- 2}^{2} \frac{1}{4 + x^{2}} d x$ 1) $\frac{π}{3}$
B) $\int_{1}^{2} \frac{1}{x \sqrt{x^{2} - 1}} d x$ 2) 0
C) $\int_{0}^{π} \cos 3 x . \cos 2 x d x$ 3) $\frac{π}{4}$
4) $\frac{π}{2}$
The correct match for List I from List II

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$A - 3; B - 1; C - 4$

$A - 3; B - 1; C - 2$

$A - 1; B - 3; C - 2$

$A - 4; B - 1; C - 2$

answer is B.

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Detailed Solution

$A = \frac{1}{2} \tan^{- 1} (\frac{x}{2}) B = {(\sec^{- 1})}_{_{1}}^{^{2}} C = \int_{0}^{2 a} f (x) d x = 0 i f f (2 a - x) = - f (x)$

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	List I		List II
A)	$\int_{- 2}^{2} \frac{1}{4 + x^{2}} d x$	1)	$\frac{π}{3}$
B)	$\int_{1}^{2} \frac{1}{x \sqrt{x^{2} - 1}} d x$	2)	0
C)	$\int_{0}^{π} \cos 3 x . \cos 2 x d x$	3)	$\frac{π}{4}$
		4)	$\frac{π}{2}$

Observe the following lists List I List IIA)∫−2214+x2dx1)π3B)∫121xx2−1dx2)0C)∫0πcos3x.cos2x dx3)π4 4)π2The correct match for List I from List II

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Observe the following lists
List I List II
A) $\int_{- 2}^{2} \frac{1}{4 + x^{2}} d x$ 1) $\frac{π}{3}$
B) $\int_{1}^{2} \frac{1}{x \sqrt{x^{2} - 1}} d x$ 2) 0
C) $\int_{0}^{π} \cos 3 x . \cos 2 x d x$ 3) $\frac{π}{4}$
4) $\frac{π}{2}$
The correct match for List I from List II