Q.

Obtain an expression for the emf induced across a conductor which is moved in a uniform magnetic field which is perpendicular to the plane of motion.

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Detailed Solution

1. Consider a straight conductor (PQ) moving in uniform magnetic field
2. If the rod (PQ) is moved towards right with a constant velocity (V) area of cross section changes
 

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3. The magnetic flux enclosed by the loop PQRS is ϕ=BA=B(lx)
4. According to faraday’s law, the induced e.m.f is
ε=dt=d(Blx)dt=Bldxdt=Blv
This is known as motional induced e.m.f.

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