Q.

Of the three independent events E1E2, and E3, the probability that only E1 occurs is  α only E2 occurs is  β and only E3 occurs is γ . Let the probability P that none of events E1E2E3  occurs is satisfy the equations (α2β)P=αβandβ3γP=2βγ . All the given probabilities are assumed to the lie in the internal (0, 1).
Then probabilityofoccurenceE1probabilityofoccurenceE3= 

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answer is 6.

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Detailed Solution

(6) Let  

P(E1)=x,P(E2)=yP(E3)=z P(onlyE1)=x(1y)(1z)=α.....(1) P(onlyE2)=(1x)y(1z)=β.....(2) P(onlyE3)=(1x)(1y)z=γ.....(3) P(NoneofE1,E2,E3)=(1x)(1y)(1z)=p.....(4) Given(α2β)P=αβ....(5)andβ3γP=2βγ.....(6) Form(5)pβ2pα=1x=2yForm(6)pγ3pβ=2y=3zx=6zandP(E1)P(E3)=xz=6

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