Oil of specific gravity 0.9 enters a horizontal pipe with a bend as shown if figure with speed 4 m/s and pressure  $2.8\times {10}^{5}N/m^2$. The pressure of oil at the point B is $43K_0\left(kN{m}^{-2}\right)$. The numerical value of  $K_0$ is 

By equation of continuity 
$\begin{array}{l}{A}_1{V}_A=A_2{V}_B\\ V_B=4V_A=16m/s\end{array}$
Bernoulli’s theorem at point A and B
$$\begin{gathered} P_A+\frac{1}{2}\rho V_A^2=P_B+\frac{1}{2}\rho V_B^2 \\ 2.8\times {10}^5+\frac{1}{2}\times 900\times {\left(4\right)}^2=P_B+\frac{1}{2}\times 900\times {\left(16\right)}^2 \\ {P}_B=172\times {10}^{3}N/m^2 \\ =172kN{m}^{-2}=(43\times 4)kN{m}^{-2} \\ \Rightarrow K_0=4 \end{gathered}$$