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On reaction with sodium, 1 mol of a compound X gives 1 mol of _{$H_{2} .$} Which one of the following compounds might be X?

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_{$C H_{3} C O O C H_{2} C H_{3}$}

_{$C H_{2} C H_{2} C H = C H_{2}$}

_{$C H_{3} C H_{2} C H_{2} O H$}

_{$C H_{2} O H C H_{2} C H_{2} C H_{2} O H$}

answer is D.

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Detailed Solution

Since 1 mole of compound X reacts with _{$N a$} to evolve 1 mole of _{$H_{2}$} gas, therefore the compound should have 2 active hydrogen atoms per mole which is possible only in option d.

_{$C H_{2} O H C H_{2} C H_{2} C H_{2} O H + 2 N a$}

_{$\to N a O C H_{2} C H_{2} C H_{2} O N a + H$}

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