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On a block of weight $9.8 N$ the table surface exerts an upward force of $10 N$ . For this situation mark the correct statement $(s) T a k e - g = 9.8 m / s^{2}$ .

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The block exerts a force of $10 N$ on the table

The block exerts a force of $19.8 N$ on the table

The block exerts a force of $9.8 N$ on the table

The block has an upward acceleration at the moment considered.

answer is A, D.

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Detailed Solution

A, force on surface by block = $10 N$

D, for block , $10 - 9.8 = m a$

$a = \frac{0.2}{m} = \frac{0.2}{1}$ $\Rightarrow a = 0.2 {ms}^{- 2}$ upwards

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