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On a hypothetical scale A, the ice point is 42° and the steam points is 182° . For another scale B, the ice point is –100^o and steam point is 90°. If B reads 60°, the reading of A is

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160°

140°

120°

110°

answer is A.

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Detailed Solution

$\begin{array}{l} \frac{Reading - LFP}{UFP -LFP} = constant \\ \frac{X_{A} - L_{A}}{U_{A} - L_{A}} = \frac{X_{B} - L_{B}}{U_{B} - L_{B}} \end{array}$

$\Rightarrow \frac{X_{A} - 42}{182 - 42} = \frac{60 - (- 100)}{90 - (- 100)}$

$\Rightarrow X_{A} = 159.9$

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