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Q.

On a hypothetical scale X, the ice point is 400 and the steam point is 1200. For another scale Y the ice point and steam points are –300 and 1300 respectively. If X-reads 500 The reading of Y is

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a

-80

b

-50

c

-100

d

-120

answer is C.

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Detailed Solution

X−LFPUFP−LFP= constant 50−40120−40=y+30130+30Y=−10∘C

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