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On a long horizontally moving belt, a child runs to and fro with a speed 9 km h^-1 (with respect to the belt) between his father and mother located 50 m apart. The belt moves with speed of 4 km h^-1. For an observer on a stationary platform, the speed of the child running in the direction of motion of the belt is

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4 km h^–1

5 km h^–1

9 km h^–1

13 km h^–1

answer is D.

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Detailed Solution

V_CB = 9km/h ; V_B = 4kmh^–1

V_CB = V_C – V_B

9 = V_C – 4 ⇒ V_C = 13km/hr.

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