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On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 39°W and 239°W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39°C on the Celsius scale ?

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200° W

139°W

78°W

117°W

answer is D.

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Detailed Solution

$\frac{C - 0}{100 - 0} = \frac{W - LPF}{UPF - LPF} \Rightarrow \frac{39 - 0}{100 - 0} = \frac{W - 39}{239 - 39} \Rightarrow W = 117^{o} W$

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