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On a temperature scale ‘X’, the boiling point of water is 65°X and the freezing point is -15°X. Assume that the X scale is linear. The equivalent temperature corresponding to -95°X on the Fahrenheit scale would be

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-148°F

-112°F

-48°F

-63°F

answer is D.

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Detailed Solution

$UFP = 65^{\circ} X, LFP = - 15^{\circ} X, t_{x} = - 95^{\circ} X, t_{F} = ?$
$\frac{t_{F} - 32}{180} = \frac{t_{x} - LFP}{UFP - LFP}$

$\Rightarrow \frac{t_{F} - 32}{180} = \frac{- 95 + 15}{65 + 15}$

$\Rightarrow \frac{t_{F} - 32}{180} = \frac{- 80}{80}$

$\Rightarrow t_{F} = - 180 + 32 = - 148^{\circ} F$

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