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Q.

On a temperature scale “X”, the boiling point of water is $65^{0} X$ and the freezing point is $- 15^{0} X$ . Assume that the X scale is linear. The equivalent temperature corresponding to $- 95^{0} X$ on the Fahrenheit scale would be

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a

$- 112^{0} F$

b

$- 63^{0} F$

c

$- 48^{0} F$

d

$- 148^{0} F$

answer is D.

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Detailed Solution

$U F P = 65^{0} X, L F P = - 15^{0} X t_{x} = - 95^{0} C, t_{p} = ? \frac{t_{p} - 32}{180} = \frac{t_{x} - L F P}{U F P - L F P} \frac{t_{p} - 32}{180} = \frac{- 95 (- 15)}{65 - (- 15)} = \frac{- 80}{80} t_{p} - 32 = - 180 t_{p} = - 180 + 32 = - 148^{0} F$

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