On adding potassium iodide to an aqueous solution , containing complex ion ${[A g {(N H_{3})}_{2}]}^{+}$ yellow coloured precipitate of AgI is formed. Similarly when hydroiodic acid was added to the complex ion ${[A g {(N H_{3})}_{2}]}^{+}$ again precipitates AgI. Then correct statements for these observations

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Complex ion ${[A g {(N H_{3})}_{2}]}^{+}$ is less stable than AgI

Complex ion ${[A g {(N H_{3})}_{2}]}^{+}$ ionizes less than AgI

HI neutralizes $N H_{3}$ ligands and precipitates AgI

IUPAC name of the complex is diammine silver (I) ion

answer is A, C, D.

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Detailed Solution

AgI is more stable than ${[A g {(N H_{3})}_{2}]}^{+}$ HI neutralizes NH₃ forming $N H_{4}^{+}$ ion thus it cannot act as ligand.

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