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On an inclined plane of inclination angle 30°, a block is placed. It is observed that the force to drag the block along the plane upwards is smaller than the force required to lift it. The maximum value of coefficient of friction is

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$\frac{1}{2}$

$\frac{\sqrt{3}}{2}$

$\frac{1}{\sqrt{3}}$

$\frac{2}{3}$

answer is C.

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Detailed Solution

$\begin{array}{l} F_{1} = mgsin θ + f, f = μN, N = mgcos θ \\ F_{2} = mg ∴ It is given that F_{1} < F_{2} \end{array}$

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