On analysis a certain compound was found to contain iodine and oxygen in the ratio $254 g$ of iodine and $80 g$ of oxygen The atomic mass of iodine is $127$ and that of oxygen is $16$ . What is the formula of the compound?

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Detailed Solution

The molecular mass of iodine $= 127 g / mol$
So, the molecule of iodine present in $254 g$ of iodine $= \frac{254 g}{127 g / mol}$ $= > 2 mol$

Now, the molecular mass of oxygen $= 16 g / mol$

So, the molecule of oxygen present in $80 g$ of oxygen $= \frac{80 g}{16 g / mol}$ $= > 5$

Therefore, the formula will be $I_{2} O_{5} .$ _.

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