On complete combustion 0.30 g of an organic compound gave 0.20 g of carbon dioxide and 0.10 g of water. the percentage of carbon in the given organic compound is _______

44g of CO₂ contains 12 g of C
0.2g of CO₂ contains $\left(\frac{12}{44}\times 0.2\right)\mathrm{g}$ of C, which comes from 0.3 g of organic compound
$\therefore$Percentage of carbon in the given compound $=\frac{12\times 0.2}{44\times 0.3}\times 100=18.18\mathrm{\%}$