On complete combustion of 0.492 g of an organic compound containing C, H and O, 0.7938 g of CO₂ AND 0.4428 g of H₂O was produced. The % composition of oxygen in the compound is _______

$$\begin{gathered} 0.492\mathrm{g} \mathrm{of} {\mathrm{C}}_{\mathrm{x}}{\mathrm{H}}_{\mathrm{y}}{\mathrm{O}}_{\mathrm{z}} \\ \mathrm{Gives} 0.7938\mathrm{g} {\mathrm{CO}}_2=0.018 \mathrm{moles} \\ 0.4428\mathrm{g} {\mathrm{H}}_2\mathrm{O}=0.0246 \mathrm{moles} \\ \mathrm{So} \mathrm{moles} \mathrm{of} \mathrm{C}=0.018\Rightarrow 0.216 \mathrm{g} \\ \mathrm{Moles} \mathrm{of} \mathrm{H}=0.049\Rightarrow 0.049\mathrm{g} \\ \therefore \mathrm{wt} \mathrm{of} \mathrm{Oxygen}=0.492-0.216-0.049 \\ =0.227 \mathrm{g} \\ \% \mathrm{of} \mathrm{Oxygen}=\frac{0.227}{0.492}\times 100 = 46 (\mathrm{approx}.) \end{gathered}$$