On complete combustion $0.30 \mathrm{g}$ of an organic compound gave $0.20 \mathrm{g}$ of carbon dioxide and $0.10 \mathrm{g}$ of water. The percentage of carbon in the given organic compound is ___________ (Nearest Integer)

Step 1: Calculate the mass of carbon in the CO₂ produced

The molar mass of CO₂ is:

Molar mass of CO₂ = 44 g/mol

The mass fraction of carbon in CO₂ is:

Mass fraction of C = Mass of C / Mass of CO₂ = 12 / 44

Mass of carbon in 0.20 g of CO₂:

Mass of C = (12 / 44) × 0.20 = 0.0545 g

Step 2: Calculate the percentage of carbon in the organic compound

The total mass of the organic compound is:

Mass of compound = 0.30 g

The percentage of carbon in the organic compound is:

% Carbon = (Mass of C / Mass of compound) × 100

% Carbon = (0.0545 / 0.30) × 100 = 18.17%

Final Answer:

The percentage of carbon in the organic compound is approximately 18% (nearest integer).