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On cooling of following on the equilibrium ${CO}_{2} (s) ⇌ {CO}_{2} (g)$

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More gas is formed

None of above

More gas solidifies

There is no effect on the equilibrium state

answer is C.

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Detailed Solution

$T ↓,$ then $V ↓,$ then $P ↑$ , equilibrium shifts in such direction so as to decrease pressure, i.e., backward direction.

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