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Q.

On decreasing the 𝑝H from 7 to 2, the solubility of a sparingly soluble salt (MX) of a weak acid (HX) increased from  10βˆ’4mol Lβˆ’1 to 10βˆ’3mol Lβˆ’1.  The pKa of HX is

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a

2

b

3

c

4

d

5

answer is B.

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Detailed Solution

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MX+H2Oβ‡ŒM+aq+Xβˆ’aq;Ksp=10βˆ’8
MX+H+β‡ŒM++HX;KspKa
10βˆ’2           10βˆ’3         β€‰β€‰β€‰β€‰10βˆ’3
10βˆ’8Ka=10βˆ’610βˆ’2=10βˆ’4⇒    Ka=10βˆ’4⇒    pKa=4

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