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Q.

On decreasing the 𝑝H from 7 to 2, the solubility of a sparingly soluble salt (MX) of a weak acid (HX) increased from $10^{- 4} mol L^{- 1} to 10^{- 3} mol L^{- 1} .$ The ${pK}_{a}$ of HX is

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a

2

b

3

c

4

d

5

answer is B.

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Detailed Solution

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$MX + H_{2} O ⇌ M^{+} (aq) + X^{-} (aq); K_{sp} = 10^{- 8}$
$MX + H^{+} ⇌ M^{+} + HX; \frac{K_{sp}}{K_{a}}$
$10^{- 2} 10^{- 3} 10^{- 3}$
$\frac{10^{- 8}}{K_{a}} = \frac{10^{- 6}}{10^{- 2}} = 10^{- 4} \Rightarrow K_{a} = 10^{- 4} \Rightarrow {pK}_{a} = 4$

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On decreasing the H from 7 to 2, the solubility of a sparingly soluble salt (MX) of a weak acid (HX) increased from 10−4mol L−1 to 10−3mol L−1. The pKa of HX is