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Q.

On dissolving CO2 in water, the following equilibrium is established
CO2+2H2OH3O++HCO3
for which the value of equilibrium constant is 3 .8 x 10-7 and
pH = 6.0. The HCO3CO2 ratio is

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a

13.8

b

0.38

c

1.38

d

3.8

answer is B.

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Detailed Solution

pH=pKa+logHCO3CO2 6.0=log3.8×107+logHCO3CO2 6.0=+6.42+logHCO3CO2  logHCO3CO2=0.42  HCO3CO2=0.38

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